brainpy.math.random.standard_normal#
- brainpy.math.random.standard_normal(size=None, key=None)[source]#
Draw samples from a standard Normal distribution (mean=0, stdev=1).
- Parameters:
size (int or tuple of ints, optional) – Output shape. If the given shape is, e.g.,
(m, n, k)
, thenm * n * k
samples are drawn. Default is None, in which case a single value is returned.- Returns:
out – A floating-point array of shape
size
of drawn samples, or a single sample ifsize
was not specified.- Return type:
float or ndarray
See also
normal
Equivalent function with additional
loc
andscale
arguments for setting the mean and standard deviation.
Notes
For random samples from the normal distribution with mean
mu
and standard deviationsigma
, use one of:mu + sigma * bm.random.standard_normal(size=...) bm.random.normal(mu, sigma, size=...)
Examples
>>> bm.random.standard_normal() 2.1923875335537315 #random
>>> s = bm.random.standard_normal(8000) >>> s array([ 0.6888893 , 0.78096262, -0.89086505, ..., 0.49876311, # random -0.38672696, -0.4685006 ]) # random >>> s.shape (8000,) >>> s = bm.random.standard_normal(size=(3, 4, 2)) >>> s.shape (3, 4, 2)
Two-by-four array of samples from the normal distribution with mean 3 and standard deviation 2.5:
>>> 3 + 2.5 * bm.random.standard_normal(size=(2, 4)) array([[-4.49401501, 4.00950034, -1.81814867, 7.29718677], # random [ 0.39924804, 4.68456316, 4.99394529, 4.84057254]]) # random